The Rayleigh distribution from Example 5.1.7 has PDF f(x)=x e^-x^2 / 2, x>0 . Let X have the Rayleigh distribution. (a) Find E(X) without using much calculus, by interpreting the integral in terms of known results about the Normal distribution. (b) Find E(X^2). Hint: A nice approach is to use LOTUS and the substitution u=x^2 / 2, and then interpret the resulting integral in terms of known results about the Exponential distribution. | Numerade